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JEE-ADVANCED-2015
PAPER 1
Question
A Bullet is fired vertically upwards with velocity $v$ from the surface of a spherical planet. When it reaches its maximum height, its acceleration due to the planet's gravity is $1 / 4^{\text {th }}$ of its value at the surface of the planet. If the escape velocity from the planet is $v_{\text {esc }}=v \sqrt{n}$, then the value of $N$ is (ignore energy loss due to atmosphere)
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Question Tags
JEE Advance
Physics
Easy
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